Page:Sewell Dikshit The Indian Calendar (1896) proc.djvu/114

into one or the other of these. Find (${\displaystyle a}$) (${\displaystyle b}$) (${\displaystyle c}$) (${\displaystyle t}$) (${\displaystyle s}$) (${\displaystyle n}$) for the given moment as above (Art. 156). Add (${\displaystyle s}$) to (${\displaystyle n}$). Call the sum (${\displaystyle y}$). This, as index, shews by Table VIII., cols, 11, 12, 13, the yoga current at the given moment.

Example xxiv. Find the yoga at sunrise on Jyeshṭha śukla 5th, Śaka 1702 expired, 7th June, 1780 A.D.

As calculated in example xviii.	${\displaystyle (s)=1559}$	${\displaystyle (n)=3022}$
Add (${\displaystyle n}$) to (${\displaystyle s}$)	${\displaystyle (n)=3022}$
Required yoga (${\displaystyle y}$)	4581	= (13) Vyâghâta (Table VIII.).

We find the beginning point of Vyâghâta from this.

The (${\displaystyle y}$) so found 4581 − 4444 (beginning point of Vyâghâta) = 137 = (6 h. 6 m. + 2 h. 15 m. =) 8 h. 21 m. before sunrise on Wednesday (Table X., col. 5).

The end of Vyâghâta is found thus:

(End of Vyâghâta) 4815 − 4581 (${\displaystyle y}$) = 234 = (12 h. 12 m. + 2 h. 4 m. =) 14 h. 16 m. after sunrise on Wednesday.

160. (See Art. 132.) The following is an example of the facility afforded by the Tables in this volume for verifying Indian dates.

Example xxv. Suppose an inscription to contain the following record of its date,—"Śaka 666, Kârttika kṛishṇa amâvâsyâ (30), Sunday, nakshatra Hasta." The problem is to verify this date and find its equivalent A.D. There is nothing here to shew whether the given year is current or expired, whether the given month is amânta or pûrṇimânta, and whether, if the year be the current one, the intercalary month in it was taken as true or mean.^[1]

First let us suppose that the year is an expired one (667 current) and the month amânta. There was no intercalary month in that year. The given month would therefore be the eighth, and the number of intervening months from the beginning of the year is 7.

	d.	w.	a.	b.	c.
Śaka 667 current. (Table I., cols. 19, 20, 23, 24, 25)	80	6	324	773	278
210 (7 months) + 15 (śukla) + 14 (kṛ. amâvâsyâ is 15, and 1 must be substracted by rule) = 239 tithis = 235 days	235	4	9578	59	643
	315	3	9902	302	921
Equation for (${\displaystyle b}$) (302) (Table VI.)			271
Equation forDo. (${\displaystyle c}$) (921) (Table VII.)			90
		3	263	${\displaystyle =t}$.

This gives us Tuesday, śukla 1st (Table VIII.). Index, ${\displaystyle t=263}$, proves that 263 parts of the tithi had expired at sunrise on Tuesday, and thence we learn that this śukla 1st commenced on Monday, and that the preceding tithi kṛi. 30 would possibly commence on Sunday. If so, can we connect the tithi kṛi. 30 with the Sunday? Let us see.